interro, calcul mental (version AB l'interro)
authorDenise sur Lya <sekhmet@lya>
Thu, 14 Jan 2016 21:21:11 +0000 (22:21 +0100)
committerDenise sur Lya <sekhmet@lya>
Thu, 14 Jan 2016 21:21:11 +0000 (22:21 +0100)
1ere/calcul_mental/fractions.pdf [new file with mode: 0644]
1ere/calcul_mental/fractions.tex [new file with mode: 0644]
2nde/interro_01-15/cube_lettres.pdf [new file with mode: 0644]
2nde/interro_01-15/cube_lettres.svg [new file with mode: 0644]
2nde/interro_01-15/interro.tex [new file with mode: 0644]
2nde/interro_01-15/interro_A_corrige.pdf [new file with mode: 0644]
2nde/interro_01-15/interro_A_enonce.pdf [new file with mode: 0644]
2nde/interro_01-15/interro_B_corrige.pdf [new file with mode: 0644]
2nde/interro_01-15/interro_B_enonce.pdf [new file with mode: 0644]
header.tex
latex_AB.pl [new file with mode: 0644]

diff --git a/1ere/calcul_mental/fractions.pdf b/1ere/calcul_mental/fractions.pdf
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diff --git a/1ere/calcul_mental/fractions.tex b/1ere/calcul_mental/fractions.tex
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+\input{../../header_beamer.tex}
+
+\begin{document}
+
+\slide{Fractions : remettre au même dénominateur
+
+\pause
+
+\bigskip
+
+Mettre au même dénominateur les sommes de fractions suivantes, et indiquer les valeurs interdites}
+
+\slide{
+1)
+\[
+\frac{1}{x} + 1
+\]
+}
+
+\slide{
+2) 
+
+\[ \frac{2}{x+1} - 1\]
+
+}
+
+\slide{
+3)
+
+\[\frac{1}{x} - \frac{1}{2} \]
+
+}
+
+\slide{
+4)
+
+\[\frac{3}{x+1} + \frac{1}{x-1} \]
+
+}
+
+\slide{
+5)
+\[\frac{1}{x^2 -3x -2} + 1 \]
+
+}
+
+\slide{
+\begin{enumerate}
+\item $
+\frac{1}{x} + 1
+$
+\item $\frac{2}{x+1} - 1$ \\
+\item$\frac{1}{x} - \frac{1}{2}$ \\
+\item $\frac{3}{x+1} + \frac{1}{x-1}$
+\item $\frac{1}{x^2 -3x -2} + 1$
+\end{enumerate}
+}
+
+\end{document}
diff --git a/2nde/interro_01-15/cube_lettres.pdf b/2nde/interro_01-15/cube_lettres.pdf
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diff --git a/2nde/interro_01-15/interro.tex b/2nde/interro_01-15/interro.tex
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index 0000000..96721ba
--- /dev/null
@@ -0,0 +1,61 @@
+\input{../../header.tex}
+
+\begin{document}
+\section*{Interrogation écrite --\version{A}{B} \hspace{3cm}\dateoucorr{15 janvier 2016}}
+
+
+
+\nomprenom
+
+Dans la figure suivante, $ABCDEFG$ est un cube, et $I$, $L$, $K$ et $J$ sont respectivement sur les arêtes $[AD]$, $[DC]$, $[CB]$, [$AB]$.
+
+\includegraphics[width=6cm]{cube_lettres.pdf}
+
+\section{Droites et plans de l'espace (6,5)}
+
+\begin{enumerate}
+\item Indiquer la position relative des droites et plans suivants (sans justification).\bareme{0,5 chaque}
+
+\begin{enumerate}
+\item \version{$(ABC)$ et $(GHD)$}{$(ABC)$ et $(EHG)$} : 
+\item \version{$(IJD)$ et $(LBK)$}{$(HEB)$ et $(LKJ)$} : 
+\item \version{$(ADH)$ et $(KCG)$}{$(CBH)$ et $(ADG)$} :
+\item \version{$(AF)$ et $(CH)$}{$(AF)$ et $(DI)$} : 
+\item \version{$(DJ)$ et $(GF)$}{$(AI)$ et $(LG)$} :
+\item \version{$(LK)$ et $(CD)$}{$(AJ)$ et $(LC)$} :
+\item \version{$(DI)$ et $(GF)$}{$(DH)$ et $(BF)$} :
+
+\end{enumerate}
+
+\item Étudier l'intersection des plans $(ADG)$ et \version{$(DHE)$}{$(FBG)$}. \bareme{1,5}
+
+\reponseouplace{}{\vspace{6cm}}
+
+\item Étudier l'intersection des plans $(IJK)$ et \version{$(AEF)$}{$(BCG)$}. \bareme{1,5}
+
+\reponseouplace{}{\vspace{6cm} 
+
+}
+
+\end{enumerate}
+
+\section{Calculs dans l'espace (3,5)}
+
+On reprend la même figure que précédemment, et le côté du cube est donné : \version{3}{5} cm. On suppose que le point $J$ est le milieu de $[AB]$. 
+
+
+
+\begin{enumerate}
+\item Calculer le volume de la pyramide à base $(EFGH)$ et ayant pour sommet $I$ \bareme{1,5}
+\reponseouplace{}{\vspace{5cm}}
+
+\item Calculer les distances $EJ$ et $JH$ dans ce cube (on pourra admettre que l'angle $\widehat{JEH}$ est droit).
+
+
+\end{enumerate}
+
+\vspace{13cm}
+
+\includegraphics[width=4cm]{cube_lettres.pdf}
+
+\end{document}
diff --git a/2nde/interro_01-15/interro_A_corrige.pdf b/2nde/interro_01-15/interro_A_corrige.pdf
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diff --git a/2nde/interro_01-15/interro_A_enonce.pdf b/2nde/interro_01-15/interro_A_enonce.pdf
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diff --git a/2nde/interro_01-15/interro_B_corrige.pdf b/2nde/interro_01-15/interro_B_corrige.pdf
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diff --git a/2nde/interro_01-15/interro_B_enonce.pdf b/2nde/interro_01-15/interro_B_enonce.pdf
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 \fi
 }
 
+%%%%%%%%%%%%%%%%% spécial sujets A/B %%%%%%%%%%%%%%%%%%%
+
+
+
+\newcommand{\version}[2]{
+\sujetA
+  #1
+\else
+  #2
+\fi
+}
+
diff --git a/latex_AB.pl b/latex_AB.pl
new file mode 100644 (file)
index 0000000..79ad312
--- /dev/null
@@ -0,0 +1,57 @@
+#!/usr/bin/perl
+
+$entree=$ARGV[0] ;
+
+if($entree =~ /^(.*).tex$/)
+{
+       #printf "bon" ;
+       #printf $1 ;
+       $pref=$1 ;
+       $sortieA = $pref."_A_enonce.pdf" ;
+  $sortieB = $pref."_B_enonce.pdf" ;
+       $sortieA2 = $pref."_A_corrige.pdf" ;
+       $sortieB2 = $pref."_B_corrige.pdf" ;
+       $sortiebase = $pref.".pdf" ;
+
+       #printf "fichiers : $sortie1 $sortie2\n" ;
+
+       # Génération de l'énoncé A
+       $ligne="pdflatex \"\\let\\corrige=\\iffalse\ \\let\\sujetA=\\iftrue\\input{$entree}\"" ;
+       printf "Génération de l'énoncé : $sortieA\n$ligne\n" ;
+       #printf $ligne."\n" ;
+       `$ligne` ;
+       # On déplace dans enonce
+       `mv $sortiebase $sortieA ` ;
+
+       # Génération de l'énoncé B
+       $ligne="pdflatex \"\\let\\corrige=\\iffalse\ \\let\\sujetA=\\iffalse\\input{$entree}\"" ;
+       printf "Génération de l'énoncé : $sortieB\n$ligne\n" ;
+       #printf $ligne."\n" ;
+       `$ligne` ;
+       # On déplace dans enonce
+       `mv $sortiebase $sortieB ` ; 
+
+       # Génération du corrigé A
+       $ligne="pdflatex \"\\let\\corrige=\\iftrue\ \\let\\sujetA=\\iftrue\\input{$entree}\"" ;
+       printf "Génération du corrigé : $sortieA2\n$ligne\n" ;
+       #printf $ligne."\n" ;
+       `$ligne` ;
+       # On déplace dans enonce
+       `mv $sortiebase $sortieA2 ` ;
+
+       # Génération du corrigé B
+       $ligne="pdflatex \"\\let\\corrige=\\iftrue\ \\let\\sujetA=\\iffalse\\input{$entree}\"" ;
+       printf "Génération du corrigé : $sortieB2\n$ligne\n" ;
+       #printf $ligne."\n" ;
+       `$ligne` ;
+       # On déplace dans enonce
+       `mv $sortiebase $sortieB2 ` ; 
+
+       #printf "Terminé !\n" ;
+
+}
+else
+{
+       printf "Ce n'est pas un fichier .tex !\n" ;
+       exit 1 ;
+}