interro + absurde
authorDenise sur Titasmo <denise.maurice@normalesup.org>
Fri, 15 Jan 2016 10:52:26 +0000 (11:52 +0100)
committerDenise sur Titasmo <denise.maurice@normalesup.org>
Fri, 15 Jan 2016 10:52:26 +0000 (11:52 +0100)
13 files changed:
1ere/calcul_mental/absurde.pdf [new file with mode: 0644]
1ere/calcul_mental/absurde.tex [new file with mode: 0644]
1ere/interro_01-16/exo2_figure.png [new file with mode: 0644]
1ere/interro_01-16/exo2_figures.ggb [new file with mode: 0644]
1ere/interro_01-16/exo2_figures.png [new file with mode: 0644]
1ere/interro_01-16/exo2_figuresB.ggb [new file with mode: 0644]
1ere/interro_01-16/exo2_figuresB.png [new file with mode: 0644]
1ere/interro_01-16/interro.pdf [new file with mode: 0644]
1ere/interro_01-16/interro.tex [new file with mode: 0644]
1ere/interro_01-16/interro_A_corrige.pdf [new file with mode: 0644]
1ere/interro_01-16/interro_A_enonce.pdf [new file with mode: 0644]
1ere/interro_01-16/interro_B_corrige.pdf [new file with mode: 0644]
1ere/interro_01-16/interro_B_enonce.pdf [new file with mode: 0644]

diff --git a/1ere/calcul_mental/absurde.pdf b/1ere/calcul_mental/absurde.pdf
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diff --git a/1ere/calcul_mental/absurde.tex b/1ere/calcul_mental/absurde.tex
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+\input{../../header_beamer.tex}
+
+\begin{document}
+
+\slide{
+\begin{eqnarray*}
+\pause
+& & x = -1 \\ \\
+\pause
+& \equi & x + 1 - 1 = -1 \\ \\
+\pause
+& \equi & \frac{(x+1) -1}{x+1}= \frac{-1}{x+1} \\ \\
+\pause
+& \equi & \frac{x+1}{x+1} + \frac{-1}{x+1} = \frac{-1}{x+1} \\ \\
+\pause
+& \equi & 1 + \frac{-1}{x+1} = \frac{-1}{x+1} \\ \\
+\pause
+& \equi & 1 = 0 \\
+\end{eqnarray*}
+
+
+}
+
+\end{document}
diff --git a/1ere/interro_01-16/exo2_figure.png b/1ere/interro_01-16/exo2_figure.png
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diff --git a/1ere/interro_01-16/interro.pdf b/1ere/interro_01-16/interro.pdf
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diff --git a/1ere/interro_01-16/interro.tex b/1ere/interro_01-16/interro.tex
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+\input{../../header.tex}
+
+\begin{document}
+\section*{Interrogation écrite --\version{A}{B} \hspace{3cm}\dateoucorr{16 janvier 2016}}
+
+
+
+\nomprenom
+
+\section{Paraboles (5)}
+
+Voici quatre courbes représentatives de fonctions du second degré~: $\C_1, \C_2, \C_3, \C_4$.
+
+\version{\includegraphics[width=9cm]{exo2_figures.png}}
+{\includegraphics[width=9cm]{exo2_figuresB.png}}
+
+
+
+
+Compléter le tableau suivant~: \bareme{0,25 chaque donc 5}
+
+\noindent \begin{tabular}{|c|p{3cm}|p{2cm}|p{2cm}|p{2cm}|p{3cm}|}
+\hline
+ & Racines & Signe de $\Delta$ & Signe de $a$ & Valeur de $c$ & Coordon\-nées du sommet \\
+\hline
+$\C_1$ &\vspace{1cm} & & & &  \\
+\hline
+$\C_2$ & & & & &\vspace{1cm} \\
+\hline
+$\C_3$ & & & & & \vspace{1cm} \\
+\hline
+$\C_4$ & & & & & \vspace{1cm} \\
+\hline
+\end{tabular}
+
+\section{Tableau de variation (2,5)}
+
+Soit $f$ définie par \version{$f(x) = -x^2 + 2x -1$}{$f(x) = x^2 -x + 8 $}.  Dresser son tableau de variations. \bareme{1,5 pour le sommet comme il faut, 1 pour les phases de croissance/décroissance}
+
+\reponseouplace{}{\vspace{8cm}}
+
+\section{Équation se ramenant au second degré (2,5)}
+
+Résoudre l'équation suivante (en valeur exacte), après avoir déterminé les valeurs interdites~:
+
+\[ \frac{1}{x} + 2x = 3\]
+
+\reponse{Valeur interdite~: $x=0$.
+
+\begin{eqnarray*} \frac{1}{x} + x = 3 & \equi & \frac{1}{x} + \frac{2x^2}{x} - \frac{3x}{x} = 0 \\
+& \equi & \frac{2 + x^2 -3x}{x} = 0 \\
+& \equi & x^2 -3x + 2 = 0\\
+
+}
+
+
+\end{document}
diff --git a/1ere/interro_01-16/interro_A_corrige.pdf b/1ere/interro_01-16/interro_A_corrige.pdf
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diff --git a/1ere/interro_01-16/interro_A_enonce.pdf b/1ere/interro_01-16/interro_A_enonce.pdf
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diff --git a/1ere/interro_01-16/interro_B_corrige.pdf b/1ere/interro_01-16/interro_B_corrige.pdf
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