}
/**
- * Find all tags with associated entries per user.
+ * Find all tags per user.
+ * Instead of just left joined on the Entry table, we select only id and group by id to avoid tag multiplication in results.
+ * Once we have all tags id, we can safely request them one by one.
+ * This'll still be fastest than the previous query.
*
* @param int $userId
*
* @return array
*/
- public function findAllTagsWithEntries($userId)
+ public function findAllTags($userId)
{
- return $this->createQueryBuilder('t')
+ $ids = $this->createQueryBuilder('t')
+ ->select('t.id')
->leftJoin('t.entries', 'e')
->where('e.user = :userId')->setParameter('userId', $userId)
+ ->groupBy('t.id')
+ ->orderBy('t.slug')
->getQuery()
- ->getResult();
+ ->getArrayResult();
+
+ $tags = [];
+ foreach ($ids as $id) {
+ $tags[] = $this->find($id);
+ }
+
+ return $tags;
}
/**
->getQuery()
->getSingleResult();
}
+
+ public function findForArchivedArticlesByUser($userId)
+ {
+ $ids = $this->createQueryBuilder('t')
+ ->select('t.id')
+ ->leftJoin('t.entries', 'e')
+ ->where('e.user = :userId')->setParameter('userId', $userId)
+ ->andWhere('e.isArchived = true')
+ ->groupBy('t.id')
+ ->orderBy('t.slug')
+ ->getQuery()
+ ->getArrayResult();
+
+ $tags = [];
+ foreach ($ids as $id) {
+ $tags[] = $this->find($id);
+ }
+
+ return $tags;
+ }
}